Group Anagrams
// https://www.techiedelight.com/group-anagrams-together-given-list-words/
/*
Given a list of words, efficiently group all anagrams.
The two strings, X and Y, are anagrams if by rearranging X's letters, we can get Y using all the original letters of X exactly once.
For example, all these pairs are anagrams as lhs can be rearranged to rhs and vice-versa.
actors = costar
altered = related
auctioned = education
aspired = despair
mastering = streaming
recurd = secured
Ex1:
Input:
[CARS, REPAID, DUES, NOSE, SIGNED, LANE, PAIRED, ARCS, GRAB, USED, ONES, BRAG, SUED, LEAN, SCAR, DESIGN]
Output:
GRAB BRAG
CARS ARCS SCAR
REPAID PAIRED
LANE LEAN
SIGNED DESIGN
DUES USED SUED
NOSE ONES
*/
#include <vector>
#include <string>
#include <unordered_map>
#include <cassert>
#include <iostream>
using namespace std;
string encodeStr(string str) {
unordered_map<char, int> m;
int n = str.size();
for (char c : str) {
m[c]++;
}
string res;
for (int i = 0; i < 26; i++) {
char c = i + 'a';
if (!m.count(c)) continue;
res.push_back(c);
res.push_back('0'+m[c]);
}
for (int i = 0; i < 26; i++) {
char c = i + 'A';
if (!m.count(c)) continue;
res.push_back(c);
res.push_back('0' + m[c]);
}
return res;
}
vector<vector<string>> groupAnagrams(vector<string> strs) {
if (strs.empty()) {
return {};
}
unordered_map<string, vector<string>> anagramMap;
int n = strs.size();
for (int i = 0; i < n; i++) {
string hash = encodeStr(strs[i]);
anagramMap[hash].push_back(strs[i]);
}
vector<vector<string>> res;
for (auto i : anagramMap) {
res.push_back(i.second);
}
return res;
}
int main() {
vector<string> input = { "CARS", "REPAID", "DUES", "NOSE", "SIGNED", "LANE", "PAIRED", "ARCS", "GRAB", "USED", "ONES", "BRAG", "SUED", "LEAN", "SCAR", "DESIGN" };
vector<vector<string>> expectedOutput = {
{"CARS", "ARCS", "SCAR"},
{"REPAID", "PAIRED"},
{"DUES", "USED", "SUED"},
{"NOSE", "ONES"},
{"SIGNED", "DESIGN"},
{"LANE", "LEAN"},
{"GRAB", "BRAG"}
};
vector<vector<string>> result = groupAnagrams(input);
// Sort the result and expectedOutput vectors to compare them
sort(result.begin(), result.end());
sort(expectedOutput.begin(), expectedOutput.end());
for (int i = 0; i < result.size(); i++) {
for (int j = 0; j < result[i].size(); j++) {
cout << result[i][j] << " ";
}
cout << endl;
}
assert(result == expectedOutput);
cout << "Test passed!" << endl;
return 0;
}```
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